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*Class Ix Rs Aggarwal All Chapter Pdf Download Online
*Class Ix Rs Aggarwal All Chapter Pdf Download Pdf
*Class Ix Rs Aggarwal All Chapter Pdf Download Free
Rs Aggarwal 2019 2020 Solutions for Class 9 Maths Chapter 5 Coordinate Geometry are provided here with simple step-by-step explanations. These solutions for Coordinate Geometry are extremely popular among Class 9 students for Maths Coordinate Geometry Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2019 2020 Book of Class 9 Maths Chapter 5 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2019 2020 Solutions. All Rs Aggarwal 2019 2020 Solutions for class Class 9 Maths are prepared by experts and are 100% accurate.
Class Ix Rs Aggarwal All Chapter Pdf Download Passport Ensemble Tub Not Turning On Easy Driver Pack Windows 7 32 Bit How To Fast Travel In Dead Island Starbound How. Download or Read: SOLUTION OF RS AGGARWAL MATHS CLASS 10 PDF Here! The writers of Solution Of Rs Aggarwal Maths Class 10 have made all reasonable attempts to offer latest and precise information and facts for the readers of this publication. The creators will not be held accountable for any unintentional flaws or omissions that may be found. CLASS IX RS Aggarwal solutions TRIANGLES- CHAPTER 8 EXERCISE 8 Answer1 In ABC, given ∠B=76° and ∠C= 48° Sum of all the angles of a is 180° ∴ ∠A+∠B+∠C = 180 ∠A = 180 - ∠C - ∠B ∠A = 180- 76 -48 ∠A = 56° Answer2 Let the angle be x° So, the angles be 2x, 3x, 4x.Page No 174:Question 1:
On the plane of a graph paper draw X’OX and YOY’ as coordinate axes and plot each of the following points.
(i) A(5, 3)
(ii) B(6, 2)
(iii) C(–5, 3)
(iv) D(4, –6)
(v) E(–3, –2)
(vi) F(–4, 4)
(vii) G(3, –4)
(viii) H(5, 0)
(ix) I(0, 6)
(x) J(–3, 0)
(xi) K(0, –2)
(xii) O(0, 0)Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
(x)
(xi)
(xii)
Page No 175:Question 2:
Write down the coordinates of each of the points A, B, C, D, E shown below:
Answer:
Video player subtitles for mac. Draw perpendicular AL, BM, CN, DP and EQ on the X-axis.
(i) Distance of A from the Y-axis = OL = -6 units
Distance of A from the X-axis = AL = 5 units
Hence, the coordinates of A are (-6,5).
(ii) Distance of B from the Y-axis = OM = 5 units
Distance of B from the X-axis = BM = 4 units
Hence, the coordinates of B are (5,4).
(iii) Distance of C from the Y-axis = ON = -3 units
Distance of C from the X-axis = CN = 2 units
Hence, the coordinates of C are (-3,2).
(iv) Distance of D from the Y-axis = OP = 2 units
Distance of D from the X-axis = DP = -2 units
Hence, the coordinates of D are (2,-2).
(v) Distance of E from the Y-axis = OL = -1 units
Distance of E from the X-axis = AL = -4 units
Hence, the coordinates of E are (-1,-4).Page No 175:Question 3:
For each of the following points, write the quadrant in which it lies
(i) (–6, 3)
(ii) (–5, –3)
(iii)(11, 6)
(iv) (1, –4)
(v) (–7, –4)
(vi) (4, –1)
(vii) (–3, 8)
(viii) (3, –8)Answer:
(i) (–6, 3)
Points of the type (–, +) lie in the II quadrant.
Hence, the point lies (–6, 3) in the II quadrant.
(ii) (–5, –3)
Points of the type (–, –) lie in the III quadrant.
Hence, the point lies (–5, –3) in the III quadrant.
(iii)(11, 6)
Points of the type (+, +) lie in the I quadrant.
Hence, the point lies (11, 6) in the I quadrant.
(iv) (1, –4)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (1, –4) in the IV quadrant.
(v) (–7, –4)
Points of the type (–, –) lie in the III quadrant.
Hence, the point lies (–7, –4) in the III quadrant.
(vi) (4, –1)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (4, –1) in the IV quadrant.
(vii) (–3, 8)
Points of the type (–, +) lie in the II quadrant.
Hence, the point lies (–3, 8) in the II quadrant.
(viii) (3, –8)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (3, –8) in the IV quadrant.Page No 175:Question 4:
Write the axis on which the given point lies.
(i) (2, 0)
(ii) (0, –5)
(iii) (–4, 0)
(iv) (0, –1)Answer:
(i) (2, 0)
The ordinate of the point (2, 0) is zero.
Hence, the (2, 0) lies on the x-axis.
(ii) (0, –5)
The abscissa of the point (0, –5) is zero.
Hence, the (0, –5) lies on the y-axis.
(iii) (–4, 0)
The ordinate of the point (–4, 0) is zero.
Hence, the (–4, 0) lies on the x-axis.
(iv) (0, –1)
The abscissa of the point (0, –1) is zero.
Hence, the (0, –1) lies on the y-axis.Page No 175:Question 5:
Which of the following points lie on the x-axis?
(i) A(0, 8)
(ii) B(4, 0)
(iii) C(0, –3)
(iv) D(–6, 0)
(v) E(2, 1)
(vi) F(–2, –1)
(vii) G(–1, 0)
(viii) H(0, –2)Answer:
(i) A(0, 8)
The given point does not lies on the x-axis.
(ii) B(4, 0)
The ordinate of the point (4, 0) is zero.
Hence, the (4, 0) lies on the x-axis.
(iii) C(0, –3)
The given point does not lies on the x-axis.
(iv) D(–6, 0)
The ordinate of the point (–6, 0) is zero.
Hence, the (–6, 0) lies on the x-axis.
(v) E(2, 1)
The given point does not lies on the x-axis.
(vi) F(–2, –1)
The given point does not lies on the x-axis.
(vii) G(–1, 0)
The ordinate of the point (–1, 0) is zero.
Hence, the (–1, 0) lies on the x-axis.
(viii) H(0, –2)
The given point does not lies on the x-axis.Page No 175:Question 6:
Plot the points A(2, 5), B(–2, 2) and C(4, 2) on a graph paper. Join AB, BC and AC. Calculate the area of ∆ABC.Answer:
Abscissa of D = Abscissa of A = 2
Ordinate of D = Ordinate of B = 2
Now,
BC = (2 + 4) units = 6 units
AD = (5 – 2) units = 3 units
Areaof∆ABC=12×Base×Height=12×BC×AD=12×6×3=9
Hence, area of ∆ABC is 9 square units.Page No 175:Question 7:
Three vertices of a rectangle ABCD are A(3, 1), B(–3, 1) and C(–3, 3). Plot these points on a graph paper and find the coordinates of the fourth vertex D. Also, find the area of rectangle ABCD.Answer:
Let A(3, 1), B(–3, 1) and C(–3, 3) be three vertices of a rectangle ABCD.
Let the y-axis cut the rectangle ABCD at the points P and Q respectively.
Abscissa of D = Abscissa of A = 3.
Ordinate of D = Ordinate of C = 3.
∴ coordinates of D are (3, 3).
AB = (BP + PA) = (3 + 3) units = 6 units.
BC = (OQ – OP) = (3 – 1) units = 2 units.
Ar(rectangle ABCD) = (AB × BC)
= (6 × 2) sq. units
= 12 sq. units
Hence, the area of rectangle ABCD is 12 square units.
Page No 176:Question 1:
In which quadrant does the point (–7, –4) lie?
(a) IV
(b) II
(c) III
(d) None of theseAnswer:
Points of the type (–, –) lie in the III quadrant.
The point (–7, –4) lies in the III quadrant.
Hence, the correct option is (c).Page No 176:Question 2:
If x > 0 and y < 0, then the point (x, y) lies in
(a) I
(b) III
(c) II
(d) IVAnswer:
(d) IV
Explanation:
The points of the type (+,-) lie in fourth quadrant.
Hence, the point (x,y), where x > 0 and y < 0, lies in quadrant IV.Page No 176:Question 3:
If a < 0 and b > 0, then the point (a, b) lies in quadrant
(a) IV
(b) II
(c) III
(d) none of theseAnswer:
Ans (b)
Explanation:
Points of the type (-,+) lie in the second quadrant.
Hence, the point P(a,b), where a < 0 and b > 0, lie in quadrant II.Page No 176:Question 4:
A point both of whose coordinates are negative lies in
(a) quadrant I
(b) quadrant II
(c) quadrant III
(d) quadrant IVAnswer:(c) quadrant III
Explanation:
Points of the type (-,-) lie in the third quadrant.
Page No 176:Question 5:
The points (other than origin) for which abscissa is equal to the ordinate will lie in the quadrant
(a) I only
(b) I or II
(c) I or III
(d) II or IVAnswer:
(c) I or III
Explanation:
If abscissa = ordinate, there could be two possibilities.
Either both are positive or both are negative. So, a point could be either (+,+), which lie in quadrant I or it could be of the type (-,-), which lie in quadrant III.
Hence, the points (other then the origin) for which the abscissas are equal to the ordinates lie in quadrant I or III.Page No 176:Question 6:
The points (–5, 3) and (3, –5) lie in the
(a) same quadrant
(b) II and III quadrants respectively
(c) II and IV quadrants respectively
(d) IV and II quadrants respectivelyAnswer:
The point (–5, 3) lies in the II quadrant.
The point (3, –5) lies in the IV quadrant.
Hence, the correct option is (c).Page No 176:Question 7:
Points (1, –1), (2, –2), (–3, –4), (4, –5)
(a) all lie in the II quadrant
(b) all lie in the III quadrant
(c) all lie in the IV quadrant
(d) do not lie in the same quadrantAnswer:
The point (1, –1) lies in the IV quadrant.
The point (2, –2) lies in the IV quadrant.
The point (–3, –4) lies in the III quadrant.
The point (4, –5) lies in the IV quadrant.
Hence, the correct option is (d).Page No 176:Question 8:
Point (0, –8) lies
(a) in the II quadrant
(b) in the IV quadrant
(c) on the x-axis
(d) on the y-axisAnswer:
The abscissa of the point (0, –8) is zero.
The point (0, –8) lies on the y-axis.
Hence, the correct option is (d).Page No 176:Question 9:
Point (–7, 0) lies
(a) on the negative direction of the x-axis
(b) on the negative direction of the y-axis
(c) in the III quadrant
(d) in the IV quadrantAnswer:
The point (–7, 0) lies on the negative direction of the x-axis.
Hence, the correct option is (a).
Page No 177:Question 10:
The point which lies on the y-axis at a distance of 5 units in the negative direction of the y-axis is
(a) (–5, 0)
(b) (0, –5)
(c) (5, 0)
(d) (0, 5)Answer:
The point which lies on the y-axis at a distance of 5 units in the negative direction of the y-axis is (0, –5).
Hence, the correct option is (b).Page No 177:Question 11:
The ordinate of every point on the x-axis is
(a) 1
(b) –1
(c) 0
(d) any real numberAnswer:
The ordinate of every point on the x-axis is 0.
Hence, the correct option is (c).Page No 177:Question 12:
If the y-coordinate of a point is zero then this point always lies
(a) on the y-axis
(b) on the x-axis
(c) in the I quadrant
(d) in the IV quadrantAnswer:
The coordinates of a point on the x-axis are of the form (x, 0) and that of the point on the y-axis is of the form (0, y).
Thus, if the y-coordinate of a point is zero, then this point always lies on the x-axis.
Hence, the correct answer is option (b).Page No 177:Question 13:
If O(0, 0), A(3, 0), B(3, 4), C(0, 4) are four given points then the figure OABC is a
(a) square
(b) rectangle
(c) trapezium
(d) rhombusAnswer:
The point O(0, 0) is the origin.
A(3, 0) lies on the positive direction of x-axis.
B(3, 4) lies in the Ist quadrant.
C(0, 4) lies on the positive direction of y-axis.
The points O(0, 0), A(3, 0), B(3, 4) and C(0, 4) can be plotted on the Cartesian plane as follows:
Here, the figure OABC is a rectangle.
Hence, the correct answer is option (b).Page No 177:Question 14:
If A(–2, 3) and B(–3, 5) are two given points then (abscissa of A) – (abscissa of B) = ?
(a) –2
(b) 1
(c) –1
(d) 2Answer:
The given points are A(–2, 3) and B(–3, 5).
Abscissa of A = x-coordinate of A = –2
Abscissa of B = x-coordinate of B = –3
∴ Abscissa of A – Abscissa of B = –2 – (–3) = –2 + 3 = 1
Hence, the correct answer is option (b).Page No 177:Question 15:
The perpendicular distance of the point A(3, 4) from the y-axis is
(a) 3
(b) 4
(c) 5
(d) 7Answer:
The perpendicular distance of a point from the y-axis is equal to the x-coordinate of the point.
∴ Perpendicular distance of the point A(3, 4) from the y-axis = x-coordinate of A(3, 4) = 3
Hence, the correct answer is option (a).Page No 177:Question 16:
Abscissa of a point is positive in
(a) I and II quadrants
(b) I and IV quadrants
(c) I quadrant only
(d) II quadrant onlyAnswer:
(b) I and IV quadrants
Explanation:
If abscissa of a point is positive, then the ordinate could be either positive or negative.
It means that the type of any point can be either (+,+) or (+, -).
Points of the type (+,+) lie in quadrant I, whereas points of the type (+,-) lie in quadrant IV.Page No 177:Question 17:
The point at which the two coordinate axes meet is called
(a) the abscissa
(b) the ordinate
(c) the origin
(d) the quadrantAnswer:
(c) the origin
Explanation: The point at which two axes meet is called as the origin.Page No 177:Question 18:
The point whose ordinate is 3 and which lies on the y-axis is
(a) (3, 0)
(b) (0, 3)
(c) (3, 3)
(d) (1, 3)Class Ix Rs Aggarwal All Chapter Pdf Download OnlineAnswer:
The ordinate of a point is the y-coordinate of the point. So, the y-coordinate of the point is 3.
Also, any point on the y-axis has coordinates in the form (0, y).
Thus, the point whose ordinate is 3 and which lies on the y-axis is (0, 3).
Hence, the correct answer is option (b).Page No 177:Question 19:
Which of the following points lies on the line y = 2x + 3?
(a) (2, 8)
(b) (3, 9)
(c) (4, 12)
(d) (5, 15)Answer:
(b) (3,9)
Explanation:
Point (2,8) does not satisfy the equation y = 2x + 3. (∵ y = 2 × 2 + 8 = 12≠ 8)
Point (3,9) satisfy the equation y = 2x + 3. (∵ y =2 × 3 + 3 = 9)
Point (4,12) does not satisfy the equation y = 2x + 3. (∵ y = 2 × 4 + 3 = 11≠ 12)
Point (5,15) does not satisfy the equation y = 2x +3. (∵ y= 2 × 5 + 3 = 13≠15)
Hence, the point (3,9) lies on the line y = 2x +3. Page No 177:Question 20:
Which of the following points does not lie on the line y = 3x + 4?
(a) (1, 7)
(b) (2, 0)
(c) (−1, 1)
(d) (4, 12)Answer:Class Ix Rs Aggarwal All Chapter Pdf Download Pdf
(d) (4,12)
Explanation:
(a) Point (1,7) satisfy the equation y = 3x + 4. (∵y = 3 × 1 + 4 = 7)
(b) Point (2,10) satisfy the equation y = 3x + 4. (∵y = 3 × 2 + 4 = 10)
(c) Point (-1,1) satisfy the equation y = 3x + 4. (∵y = 3 × -1 + 4 = 1)
(d) Point (4,12) does not satisfy the equation y = 3x + 4. (∵ y = 3 × 4 + 4 = 16 ≠ 12)
Hence, the point (4,12) do not lie on the line y = 3x +4.Page No 177:Question 21:
Which of the following points does not lie in any quadrant?
(a) (3, –6)
(b) (–3, 4)
(c) (5, 7)
(d) (0, 3)Answer:
The point (3, –6) lies in the fourth quadrant.
The point (–3, 4) lies in the second quadrant.
The point (5, 7) lies in the first quadrant.
The point (0, 3) lies on the positive direction of y-axis.
Thus, the point (0, 3) does not lie in any quadrant.
Hence, the correct answer is option (d).Page No 177:Question 22:
The area of ∆AOB having vertices A(0, 6), O(0, 0) and B(6, 0) is
(a) 12 sq units
(b) 36 sq units
(c) 18 sq units
(d) 24 sq unitsAnswer:
The points A(0, 6), O(0, 0) and B(6, 0) can be plotted on the Cartesian plane as follows:
Here, ∆AOB is a right triangle right angled at O.
OA = 6 units and OB = 6 units
∴ Area of ∆AOB = 12×OA×OB=12×6×6 = 18 square units
Hence, the correct answer is option (c).
View NCERT Solutions for all chapters of Class 9
RS Aggarwal Solutions Class 10 Maths Chapter 16: Class 10 exams are the Major turning point in Student’s Life, In CBSE Class 10 Board Exams, Except All other Subjects, Mathematics is a bit Tricky and Interesting Subject. But Most of the Students think Maths will be toughest and Difficult to score Good Marks in It. But Don’t worry, to solve All your Class 10 Maths Preparation Problems, RS Aggarwal Class 10 Maths Solutions Came into Existence where They provide solutions for Every Chapter of Class 10 Maths with all the Exercise Problems Covered here will be discussing RS Aggarwal Solutions Class 10 Maths Chapter 16.RS Aggarwal Solutions Class 10 Maths Chapter 16 – Co-Ordinate Geometry PDF
Co-Ordinate Geometry is the sixteenth Chapter in CBSE Class 10 Maths. Chapter 16 Explains all about Introduction and Problems Related to Co-ordinate geometry. There are many Exercises to make a better understanding of the topics.
The Main Topics of Co-Ordinate Geometry Are
*Introduction to Co-Ordinate Geometry
*Calculating Distance between two points.
*Section formula and Mid-point formula
*Centroid and area of a triangle
RS Aggarwal Class 10 Maths Chapter 16 Exercises – Co-Ordinate Geometry
RS Aggarwal Chapter 16 Solutions for Class 10 maths Includes following Exercises Solutions PDFAdvantages of RS Aggarwal Solutions Class 10 Maths Chapter 16
*Includes Complete Solutions in Detailed Manner
*Easy to understand the Concept and lasts long in students Mind
*Helps in the preparation of Competitive Exams
*Strong Foundation for Class 12 MathsChapter-wise CBSE Class 10 Maths RS Aggarwal Solutions PDF
Download all chapter-wise RS Aggarwal CBSE Class 10 Mathematics Solutions to score More Marks in the Exam
*Chapter-16 Co-Ordinate Geometry
We have covered the detailed guide on RS Aggarwal Solutions for Class 10 Maths Chapter-16 Co-Ordinate Geometry. Feel free to ask us any questions in the comment section below.Class Ix Rs Aggarwal All Chapter Pdf Download FreeRelated posts:
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*Class Ix Rs Aggarwal All Chapter Pdf Download Online
*Class Ix Rs Aggarwal All Chapter Pdf Download Pdf
*Class Ix Rs Aggarwal All Chapter Pdf Download Free
Rs Aggarwal 2019 2020 Solutions for Class 9 Maths Chapter 5 Coordinate Geometry are provided here with simple step-by-step explanations. These solutions for Coordinate Geometry are extremely popular among Class 9 students for Maths Coordinate Geometry Solutions come handy for quickly completing your homework and preparing for exams. All questions and answers from the Rs Aggarwal 2019 2020 Book of Class 9 Maths Chapter 5 are provided here for you for free. You will also love the ad-free experience on Meritnation’s Rs Aggarwal 2019 2020 Solutions. All Rs Aggarwal 2019 2020 Solutions for class Class 9 Maths are prepared by experts and are 100% accurate.
Class Ix Rs Aggarwal All Chapter Pdf Download Passport Ensemble Tub Not Turning On Easy Driver Pack Windows 7 32 Bit How To Fast Travel In Dead Island Starbound How. Download or Read: SOLUTION OF RS AGGARWAL MATHS CLASS 10 PDF Here! The writers of Solution Of Rs Aggarwal Maths Class 10 have made all reasonable attempts to offer latest and precise information and facts for the readers of this publication. The creators will not be held accountable for any unintentional flaws or omissions that may be found. CLASS IX RS Aggarwal solutions TRIANGLES- CHAPTER 8 EXERCISE 8 Answer1 In ABC, given ∠B=76° and ∠C= 48° Sum of all the angles of a is 180° ∴ ∠A+∠B+∠C = 180 ∠A = 180 - ∠C - ∠B ∠A = 180- 76 -48 ∠A = 56° Answer2 Let the angle be x° So, the angles be 2x, 3x, 4x.Page No 174:Question 1:
On the plane of a graph paper draw X’OX and YOY’ as coordinate axes and plot each of the following points.
(i) A(5, 3)
(ii) B(6, 2)
(iii) C(–5, 3)
(iv) D(4, –6)
(v) E(–3, –2)
(vi) F(–4, 4)
(vii) G(3, –4)
(viii) H(5, 0)
(ix) I(0, 6)
(x) J(–3, 0)
(xi) K(0, –2)
(xii) O(0, 0)Answer:
(i)
(ii)
(iii)
(iv)
(v)
(vi)
(vii)
(viii)
(ix)
(x)
(xi)
(xii)
Page No 175:Question 2:
Write down the coordinates of each of the points A, B, C, D, E shown below:
Answer:
Video player subtitles for mac. Draw perpendicular AL, BM, CN, DP and EQ on the X-axis.
(i) Distance of A from the Y-axis = OL = -6 units
Distance of A from the X-axis = AL = 5 units
Hence, the coordinates of A are (-6,5).
(ii) Distance of B from the Y-axis = OM = 5 units
Distance of B from the X-axis = BM = 4 units
Hence, the coordinates of B are (5,4).
(iii) Distance of C from the Y-axis = ON = -3 units
Distance of C from the X-axis = CN = 2 units
Hence, the coordinates of C are (-3,2).
(iv) Distance of D from the Y-axis = OP = 2 units
Distance of D from the X-axis = DP = -2 units
Hence, the coordinates of D are (2,-2).
(v) Distance of E from the Y-axis = OL = -1 units
Distance of E from the X-axis = AL = -4 units
Hence, the coordinates of E are (-1,-4).Page No 175:Question 3:
For each of the following points, write the quadrant in which it lies
(i) (–6, 3)
(ii) (–5, –3)
(iii)(11, 6)
(iv) (1, –4)
(v) (–7, –4)
(vi) (4, –1)
(vii) (–3, 8)
(viii) (3, –8)Answer:
(i) (–6, 3)
Points of the type (–, +) lie in the II quadrant.
Hence, the point lies (–6, 3) in the II quadrant.
(ii) (–5, –3)
Points of the type (–, –) lie in the III quadrant.
Hence, the point lies (–5, –3) in the III quadrant.
(iii)(11, 6)
Points of the type (+, +) lie in the I quadrant.
Hence, the point lies (11, 6) in the I quadrant.
(iv) (1, –4)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (1, –4) in the IV quadrant.
(v) (–7, –4)
Points of the type (–, –) lie in the III quadrant.
Hence, the point lies (–7, –4) in the III quadrant.
(vi) (4, –1)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (4, –1) in the IV quadrant.
(vii) (–3, 8)
Points of the type (–, +) lie in the II quadrant.
Hence, the point lies (–3, 8) in the II quadrant.
(viii) (3, –8)
Points of the type (+, –) lie in the IV quadrant.
Hence, the point lies (3, –8) in the IV quadrant.Page No 175:Question 4:
Write the axis on which the given point lies.
(i) (2, 0)
(ii) (0, –5)
(iii) (–4, 0)
(iv) (0, –1)Answer:
(i) (2, 0)
The ordinate of the point (2, 0) is zero.
Hence, the (2, 0) lies on the x-axis.
(ii) (0, –5)
The abscissa of the point (0, –5) is zero.
Hence, the (0, –5) lies on the y-axis.
(iii) (–4, 0)
The ordinate of the point (–4, 0) is zero.
Hence, the (–4, 0) lies on the x-axis.
(iv) (0, –1)
The abscissa of the point (0, –1) is zero.
Hence, the (0, –1) lies on the y-axis.Page No 175:Question 5:
Which of the following points lie on the x-axis?
(i) A(0, 8)
(ii) B(4, 0)
(iii) C(0, –3)
(iv) D(–6, 0)
(v) E(2, 1)
(vi) F(–2, –1)
(vii) G(–1, 0)
(viii) H(0, –2)Answer:
(i) A(0, 8)
The given point does not lies on the x-axis.
(ii) B(4, 0)
The ordinate of the point (4, 0) is zero.
Hence, the (4, 0) lies on the x-axis.
(iii) C(0, –3)
The given point does not lies on the x-axis.
(iv) D(–6, 0)
The ordinate of the point (–6, 0) is zero.
Hence, the (–6, 0) lies on the x-axis.
(v) E(2, 1)
The given point does not lies on the x-axis.
(vi) F(–2, –1)
The given point does not lies on the x-axis.
(vii) G(–1, 0)
The ordinate of the point (–1, 0) is zero.
Hence, the (–1, 0) lies on the x-axis.
(viii) H(0, –2)
The given point does not lies on the x-axis.Page No 175:Question 6:
Plot the points A(2, 5), B(–2, 2) and C(4, 2) on a graph paper. Join AB, BC and AC. Calculate the area of ∆ABC.Answer:
Abscissa of D = Abscissa of A = 2
Ordinate of D = Ordinate of B = 2
Now,
BC = (2 + 4) units = 6 units
AD = (5 – 2) units = 3 units
Areaof∆ABC=12×Base×Height=12×BC×AD=12×6×3=9
Hence, area of ∆ABC is 9 square units.Page No 175:Question 7:
Three vertices of a rectangle ABCD are A(3, 1), B(–3, 1) and C(–3, 3). Plot these points on a graph paper and find the coordinates of the fourth vertex D. Also, find the area of rectangle ABCD.Answer:
Let A(3, 1), B(–3, 1) and C(–3, 3) be three vertices of a rectangle ABCD.
Let the y-axis cut the rectangle ABCD at the points P and Q respectively.
Abscissa of D = Abscissa of A = 3.
Ordinate of D = Ordinate of C = 3.
∴ coordinates of D are (3, 3).
AB = (BP + PA) = (3 + 3) units = 6 units.
BC = (OQ – OP) = (3 – 1) units = 2 units.
Ar(rectangle ABCD) = (AB × BC)
= (6 × 2) sq. units
= 12 sq. units
Hence, the area of rectangle ABCD is 12 square units.
Page No 176:Question 1:
In which quadrant does the point (–7, –4) lie?
(a) IV
(b) II
(c) III
(d) None of theseAnswer:
Points of the type (–, –) lie in the III quadrant.
The point (–7, –4) lies in the III quadrant.
Hence, the correct option is (c).Page No 176:Question 2:
If x > 0 and y < 0, then the point (x, y) lies in
(a) I
(b) III
(c) II
(d) IVAnswer:
(d) IV
Explanation:
The points of the type (+,-) lie in fourth quadrant.
Hence, the point (x,y), where x > 0 and y < 0, lies in quadrant IV.Page No 176:Question 3:
If a < 0 and b > 0, then the point (a, b) lies in quadrant
(a) IV
(b) II
(c) III
(d) none of theseAnswer:
Ans (b)
Explanation:
Points of the type (-,+) lie in the second quadrant.
Hence, the point P(a,b), where a < 0 and b > 0, lie in quadrant II.Page No 176:Question 4:
A point both of whose coordinates are negative lies in
(a) quadrant I
(b) quadrant II
(c) quadrant III
(d) quadrant IVAnswer:(c) quadrant III
Explanation:
Points of the type (-,-) lie in the third quadrant.
Page No 176:Question 5:
The points (other than origin) for which abscissa is equal to the ordinate will lie in the quadrant
(a) I only
(b) I or II
(c) I or III
(d) II or IVAnswer:
(c) I or III
Explanation:
If abscissa = ordinate, there could be two possibilities.
Either both are positive or both are negative. So, a point could be either (+,+), which lie in quadrant I or it could be of the type (-,-), which lie in quadrant III.
Hence, the points (other then the origin) for which the abscissas are equal to the ordinates lie in quadrant I or III.Page No 176:Question 6:
The points (–5, 3) and (3, –5) lie in the
(a) same quadrant
(b) II and III quadrants respectively
(c) II and IV quadrants respectively
(d) IV and II quadrants respectivelyAnswer:
The point (–5, 3) lies in the II quadrant.
The point (3, –5) lies in the IV quadrant.
Hence, the correct option is (c).Page No 176:Question 7:
Points (1, –1), (2, –2), (–3, –4), (4, –5)
(a) all lie in the II quadrant
(b) all lie in the III quadrant
(c) all lie in the IV quadrant
(d) do not lie in the same quadrantAnswer:
The point (1, –1) lies in the IV quadrant.
The point (2, –2) lies in the IV quadrant.
The point (–3, –4) lies in the III quadrant.
The point (4, –5) lies in the IV quadrant.
Hence, the correct option is (d).Page No 176:Question 8:
Point (0, –8) lies
(a) in the II quadrant
(b) in the IV quadrant
(c) on the x-axis
(d) on the y-axisAnswer:
The abscissa of the point (0, –8) is zero.
The point (0, –8) lies on the y-axis.
Hence, the correct option is (d).Page No 176:Question 9:
Point (–7, 0) lies
(a) on the negative direction of the x-axis
(b) on the negative direction of the y-axis
(c) in the III quadrant
(d) in the IV quadrantAnswer:
The point (–7, 0) lies on the negative direction of the x-axis.
Hence, the correct option is (a).
Page No 177:Question 10:
The point which lies on the y-axis at a distance of 5 units in the negative direction of the y-axis is
(a) (–5, 0)
(b) (0, –5)
(c) (5, 0)
(d) (0, 5)Answer:
The point which lies on the y-axis at a distance of 5 units in the negative direction of the y-axis is (0, –5).
Hence, the correct option is (b).Page No 177:Question 11:
The ordinate of every point on the x-axis is
(a) 1
(b) –1
(c) 0
(d) any real numberAnswer:
The ordinate of every point on the x-axis is 0.
Hence, the correct option is (c).Page No 177:Question 12:
If the y-coordinate of a point is zero then this point always lies
(a) on the y-axis
(b) on the x-axis
(c) in the I quadrant
(d) in the IV quadrantAnswer:
The coordinates of a point on the x-axis are of the form (x, 0) and that of the point on the y-axis is of the form (0, y).
Thus, if the y-coordinate of a point is zero, then this point always lies on the x-axis.
Hence, the correct answer is option (b).Page No 177:Question 13:
If O(0, 0), A(3, 0), B(3, 4), C(0, 4) are four given points then the figure OABC is a
(a) square
(b) rectangle
(c) trapezium
(d) rhombusAnswer:
The point O(0, 0) is the origin.
A(3, 0) lies on the positive direction of x-axis.
B(3, 4) lies in the Ist quadrant.
C(0, 4) lies on the positive direction of y-axis.
The points O(0, 0), A(3, 0), B(3, 4) and C(0, 4) can be plotted on the Cartesian plane as follows:
Here, the figure OABC is a rectangle.
Hence, the correct answer is option (b).Page No 177:Question 14:
If A(–2, 3) and B(–3, 5) are two given points then (abscissa of A) – (abscissa of B) = ?
(a) –2
(b) 1
(c) –1
(d) 2Answer:
The given points are A(–2, 3) and B(–3, 5).
Abscissa of A = x-coordinate of A = –2
Abscissa of B = x-coordinate of B = –3
∴ Abscissa of A – Abscissa of B = –2 – (–3) = –2 + 3 = 1
Hence, the correct answer is option (b).Page No 177:Question 15:
The perpendicular distance of the point A(3, 4) from the y-axis is
(a) 3
(b) 4
(c) 5
(d) 7Answer:
The perpendicular distance of a point from the y-axis is equal to the x-coordinate of the point.
∴ Perpendicular distance of the point A(3, 4) from the y-axis = x-coordinate of A(3, 4) = 3
Hence, the correct answer is option (a).Page No 177:Question 16:
Abscissa of a point is positive in
(a) I and II quadrants
(b) I and IV quadrants
(c) I quadrant only
(d) II quadrant onlyAnswer:
(b) I and IV quadrants
Explanation:
If abscissa of a point is positive, then the ordinate could be either positive or negative.
It means that the type of any point can be either (+,+) or (+, -).
Points of the type (+,+) lie in quadrant I, whereas points of the type (+,-) lie in quadrant IV.Page No 177:Question 17:
The point at which the two coordinate axes meet is called
(a) the abscissa
(b) the ordinate
(c) the origin
(d) the quadrantAnswer:
(c) the origin
Explanation: The point at which two axes meet is called as the origin.Page No 177:Question 18:
The point whose ordinate is 3 and which lies on the y-axis is
(a) (3, 0)
(b) (0, 3)
(c) (3, 3)
(d) (1, 3)Class Ix Rs Aggarwal All Chapter Pdf Download OnlineAnswer:
The ordinate of a point is the y-coordinate of the point. So, the y-coordinate of the point is 3.
Also, any point on the y-axis has coordinates in the form (0, y).
Thus, the point whose ordinate is 3 and which lies on the y-axis is (0, 3).
Hence, the correct answer is option (b).Page No 177:Question 19:
Which of the following points lies on the line y = 2x + 3?
(a) (2, 8)
(b) (3, 9)
(c) (4, 12)
(d) (5, 15)Answer:
(b) (3,9)
Explanation:
Point (2,8) does not satisfy the equation y = 2x + 3. (∵ y = 2 × 2 + 8 = 12≠ 8)
Point (3,9) satisfy the equation y = 2x + 3. (∵ y =2 × 3 + 3 = 9)
Point (4,12) does not satisfy the equation y = 2x + 3. (∵ y = 2 × 4 + 3 = 11≠ 12)
Point (5,15) does not satisfy the equation y = 2x +3. (∵ y= 2 × 5 + 3 = 13≠15)
Hence, the point (3,9) lies on the line y = 2x +3. Page No 177:Question 20:
Which of the following points does not lie on the line y = 3x + 4?
(a) (1, 7)
(b) (2, 0)
(c) (−1, 1)
(d) (4, 12)Answer:Class Ix Rs Aggarwal All Chapter Pdf Download Pdf
(d) (4,12)
Explanation:
(a) Point (1,7) satisfy the equation y = 3x + 4. (∵y = 3 × 1 + 4 = 7)
(b) Point (2,10) satisfy the equation y = 3x + 4. (∵y = 3 × 2 + 4 = 10)
(c) Point (-1,1) satisfy the equation y = 3x + 4. (∵y = 3 × -1 + 4 = 1)
(d) Point (4,12) does not satisfy the equation y = 3x + 4. (∵ y = 3 × 4 + 4 = 16 ≠ 12)
Hence, the point (4,12) do not lie on the line y = 3x +4.Page No 177:Question 21:
Which of the following points does not lie in any quadrant?
(a) (3, –6)
(b) (–3, 4)
(c) (5, 7)
(d) (0, 3)Answer:
The point (3, –6) lies in the fourth quadrant.
The point (–3, 4) lies in the second quadrant.
The point (5, 7) lies in the first quadrant.
The point (0, 3) lies on the positive direction of y-axis.
Thus, the point (0, 3) does not lie in any quadrant.
Hence, the correct answer is option (d).Page No 177:Question 22:
The area of ∆AOB having vertices A(0, 6), O(0, 0) and B(6, 0) is
(a) 12 sq units
(b) 36 sq units
(c) 18 sq units
(d) 24 sq unitsAnswer:
The points A(0, 6), O(0, 0) and B(6, 0) can be plotted on the Cartesian plane as follows:
Here, ∆AOB is a right triangle right angled at O.
OA = 6 units and OB = 6 units
∴ Area of ∆AOB = 12×OA×OB=12×6×6 = 18 square units
Hence, the correct answer is option (c).
View NCERT Solutions for all chapters of Class 9
RS Aggarwal Solutions Class 10 Maths Chapter 16: Class 10 exams are the Major turning point in Student’s Life, In CBSE Class 10 Board Exams, Except All other Subjects, Mathematics is a bit Tricky and Interesting Subject. But Most of the Students think Maths will be toughest and Difficult to score Good Marks in It. But Don’t worry, to solve All your Class 10 Maths Preparation Problems, RS Aggarwal Class 10 Maths Solutions Came into Existence where They provide solutions for Every Chapter of Class 10 Maths with all the Exercise Problems Covered here will be discussing RS Aggarwal Solutions Class 10 Maths Chapter 16.RS Aggarwal Solutions Class 10 Maths Chapter 16 – Co-Ordinate Geometry PDF
Co-Ordinate Geometry is the sixteenth Chapter in CBSE Class 10 Maths. Chapter 16 Explains all about Introduction and Problems Related to Co-ordinate geometry. There are many Exercises to make a better understanding of the topics.
The Main Topics of Co-Ordinate Geometry Are
*Introduction to Co-Ordinate Geometry
*Calculating Distance between two points.
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*Centroid and area of a triangle
RS Aggarwal Class 10 Maths Chapter 16 Exercises – Co-Ordinate Geometry
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*Chapter-16 Co-Ordinate Geometry
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